Question

9.5 The Head Severity Index (HST) measures the risk of head injury in a car crash. It is calculated by: HSI = 1 dit where alt) is the nomalized acceleration (acceleration in m's divided by 9.81 m's) and t is time in sec- onds during a crash. The acceleration of a dummy hend measured during a crash test is given in the follow- ing table. 0 5 10 15 20 25 30 35 40 45 50 55 60 amis 038 20 33 42 40 48 60 12 843 Determine the HSI. (a) Use the composite trapezoidal method. (b) Use the composite Simpson's 1/3 method. (c) Use the composite Simpson's 3/8 method.

Answer 1

Given dosta head service Index A SI dt 145 50 tms) 105 10 15 20/25/30/35 40 45 a bis 3/8 22 33 42 4098 60? t Find out to 1 72 73 74 is Y Y Yo Yoru 12 m Trapezoidal method: - Scelt" (y + x + 2 + 1 - --m)] Sdution! Th=6000 = 5 Cenyak [0 431 2 [+28 439 442740448 13 +218 + 8 +20+33 +42+ 4044 8+60 +12 + B +41 mm 9.81 nig? - 926.666 m/s 19 -Piet dividedby g = g. el mis2 & 94.46 mis - Set Sat = 94.66. mis I Simpsonts 13 method! - Scejde - o ** ** (/**ysty ) + (*1944

M2+ Yoty Solution: n = 6-9 = 6000-5 + 3 L + 3 + 4 (3+20+42 +46 + 12 + 4 2 CBt 33 + 40 +60 + 8 - 1361.666 m2 51 1361.666 9.61 Put divided by 7 - 961 mis => 138.80 m.5 One dt = 138.80 m. s Simpson's 3 18 method: - $ 6033684 = 3h Yo+ 2(43441-Y-2) +3 (8,4444=147)+ solutions 9 903 01 = 3x To +2(20+40 +12973 (3 +4 +33 +42 496 +60 +6+4) +3 = 14 34.375 m2, 51 -> 1934.325 Put divide by 9 = 9.61 mis 9.81 on = 196-215 m.si f = 146.218 m. Conclusion! sfalt) 72 olf = 94.66 mig = 196.80 m.s = 146.218 mes 7 all the method the values head index, to sind out service