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1 ) Problem #4 Given that data R = 1.02S2, R2 = 1.5k 2, R3 = 4.0k1, R1 = 3.0k2, and AV, = 20V (a) Find the equivalent resista

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we will draw the table in the last pagePnoblim #4 RI = I kn loo o Ra 1.5 kn 4000 n k 4 3 = 3oo0 R4 3 kn Nolt 30 (4) commuctud im guuus R4 R3 9md bya ingl sis tour oRN R+ R 000 x 10o0 7000 + 1000 R 875 ciuicuit is Now thu vudweud R2 commectad im gwrug quiu R2 Now R amd ciuTCuit is equivaforom ohms Saw SowICe cuTuunt is T 30 Reg 3375 -3 8.431 x1o I = mA 8.431 (6) I3 R3 ww Ra Ra A fom kinch hoff s cuuwunt aw Jamd R in panallel commuctud quu voJtags 9cu1088 both will bu 3qme That i2 Is R I,RI I, x lo00 capation (b we put this im mowT = I, = 8.431 VeJtags 9cu1089 RI - 3 (7.368710A) X Loo o Volt 7.368 Simidanly -3 1500 8.431 x 10 N = Ta Ra Volt 1 3. 631 V2Powun Jost thnough Ri is Ir RL 7368A 10) lo X looo P. O.05 43 Watt Janly Simi (8.421/103 X 1500 wet O.1063 Pa P3 (1.053103 40fimal tabli is tha Now cuumt (m A) Voltagu ) Powwr (wat) Ri 0.0543 于368 7.368 2.631 8.431 0.1063 R2 -3 4.208 4.426 X 10 1.053

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