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Given the following information: Buret contains .01 M EDTA; Both Solution A and B started with...

Given the following information: Buret contains .01 M EDTA; Both Solution A and B started with .042 g Calcium Magnesium Acetate; Solution A contains both magnesium and calcium; Solution B contains JUST magnesium (Ca was precipitated out); EDTA reacts with both Mg2+ and Ca2+ in a 1:1 ratio (if you use .0005 moles of EDTA, you have .0005 moles of metal ion). Titration of Solution A: Buret reading 1: 18.53 mL, Buret reading 2: 49.12 mL Titration of Solution B: Buret reading 1: 9.42 mL, Buret reading 2: 23.83 mL

a. How many mL of EDTA were needed to react completely with magnesium? How many mL of EDTA were needed to react completely with calcium?

b. Convert # mL of EDTA to # moles of Mg. Convert # mL of EDTA to # moles of Ca.

c. What is the mass percent of Mg? What is the mass percent of Ca?

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Answer #1

No. 악 14.4 n/ v Borme 16.I CG) mal 2-少 ‘.0165 39.42 % S. 6242

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