Question

Answer asap

The current-carrying loop shown in the figure has r = 2.301 m. The magnitude of the magnetic field at the dot inside the loop s 5.933 times 10^-7 T. What is the current in the loop? A 2.504 B 2.930 C 3-428 D 4.011 E 4.693 F 5.491 G 6.424 H 7.516

Answer 1

If direction of magnetic feild is inside then current should be folwing in clockwise direction of the loop.

We will use the formula which is shown in uploaded image just go through it first-

Ноге

Here both 2 horizontal wires will induced the zero magnetic feild at center then-

B_r = (4(Pi) * 10^-7)(I)(Pi/2) / (4 * pi * 2.301)

then -

B_2r = (4(Pi) * 10^-7)(I)(Pi/2) / (4 * pi *2* 2.301)

Then-

B_3r = (4(Pi) * 10^-7)(I)(Pi) / (4 * pi * 3 * 2.301)

And we know that B_r + B_2r + B_3r = 5.933 * 10^-7

(4(Pi) * 10^-7)(I) / (4 * pi * 2.301) [Pi/2 + Pi/4 + Pi/3] = 5.933 * 10^-7

I = 5.933 * 2.301 /   [Pi/2 + Pi/4 + Pi/3]

= 13.65 / 3.40

I = 4.01 (Option D)

Thank you !!! Have fun