Question

The representation of a p(t) signal in the frequency spectrum that we want to exemplify is P(f) and is shown as follows. ei P(f) = (N) S1 f 1 - 530 515KHz S/ f 15 545KHz 10 otherwise We want to record this signal by passing it through an analog to digital converter (ADC) with sampling rate of 100 KHz. Will there be an overlap? Why is that? If there is an overlap, what should be the minimum sampling rate of the ADC so that it does not exist? If the sampling rate of the ADC will remain at 100 KHz and it is possible to change the signal by performing 2 operations (operations) before ADC, what should you do so that you can record the signal without overlapping and regain the original signal when the operations are applied in reverse order?

Answer 1

801 IP(A) M - SW5 - 530-515 515 530 545 - f (kuz) been Sampling theorem, statuss that a signal a (1) must be Sampled at a rate grater than its bandwidth, a rate grater than twice its highest drequncey ds > 1090 kHz but when we sampled less than the rate of fs aliasing will occur Here sampling drequnce is 100kHz Hence areasing will occur. Ismin : logoKHZ it the sampling rate of the ADC remain we use a scheme H (JW) Plt) - ♡ > > Uptt) Low Passtiller cutoff 50kH2 j9 (500 kuz) t 8,-E8Ct-on (1006n2) lookHz where Plt) multiply a complex-exponential and then passing through a Low Pass filter and than Sampling at a trequncey of 100kHz