Question

This is done with Matlab

If an object is heated, the temperature of the body will increase. The energy (Q) associated with a change in temperature (AT) is a function of the mass of the object (m) and the spe- cific heat In an experiment, heat is applied to the end of an object, and the temperature change at the other end of the object is recorded. This leads to the theoretical relationship shown. An unknown material is tested in the lab, yielding the following results: AT mC Heat applied (Q) Jl 12 17 25 40 50 58 Temp change (AT) [K] 1.500 2.00 3.25 5.00 6.25 7.00

This is done with Matlab

Answer 1

`Hey,

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clc;

clear all;

close all;

Q=[12 17 25 40 50 58];

delta_T=[1.50 2.00 3.25 5.00 6.25 7.0];

x=Q;

y=delta_T;

figure;

plot(x,y,'or'); hold on

xlabel('\it Q [J] \rightarrow');

ylabel('\it delta T [K] \rightarrow');

%(b)

n=1;% Linear regression

A=polyfit(x,y,n); %fit a n order polynomial

% A will be a vector of the coefficients for :

% a0+a1*x+a2*x^2+.............+an*x^n

Mn=min(x);

Mx=max(x);

xx=[Mn-1:(Mx-Mn)/100:Mx+1];

yy=polyval(A,xx);% generates expected values for each value of xx

plot(xx,yy,'b');

legend('Scatter data','Linear model');

fprintf('\n delta T = %0.4f + %0.4fQ\n',A(2),A(1));

OUTPUT:

delta T = 0.0578 + 0.1220Q

O - Scatter data Linear model deka TIK] → 15 20 25 30 40 45 50 55 60 35 Q[j] →

Kindly revert for any queries

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