Question

Some numbers are not normally distributed. If the mean of the numbers is 38 and the standard deviation is 6, what proportion of values fall? would fall between 26 and 507 what proportion of values would fall between 14 and 627 Between what two values would 89% of the values (Round your answers to 2 decimal places.) At least % of the values will fall between 26 and 50. At least of the values fall between 14 and 62. Betweern and at least 89% of the values fall

Answer 1

From thw given information, the mean of the number is 38 and the standard deviation is 6. Is mu = 3.8 and sigma = 6 From the cheby chevis rule, the values 26 and 50 representing mu - 2 sigma and mu + 2 sigma, Hence 750/0 (= 2/ 4 %) of the data valves falls between 26 and 50. Consider, mu - k sigma = 14 38 - 6k = 14 k = 4 From the chebychev's rule, the valves 14 and 62 representing mu - 4sigma and mu + 4 sigma . Hence, the percentage is percentage = (1- 1/K^2) % = (1- 1/42) % = 93.75 % rightarrow from the chebychev's rule 89 % of the data lines b/w (mu - 3 sigma, mu + 3 sigma) consider, mu - 3 sigma = 38 -(3 times 8) = 38 -18 = 20 mu + 3sigma = 38 + (3 times 60 = 38 + 18 = 56