Question

If an initiator has a half-life of 4b, what of this will after 8 h? If [M^-] = 2.5 times 10^-5 mol/L under -state conditions, what will [M^-] equal after (a) 30. (b) 60. and (c) 90 min?

Answer 1

Half life = 4h Time = 8h = 2ty_2 concentration left = a/4 25% of the initial concentration [M^-] = 2.5 times 10^-5 mol/lit steady state dm/dt = 0 (a) 30 min (b) 60 min (c) 90 min [M^-] = 2.5 times 10^-5 mol/lit remains constant.