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A person riding a bicycle on level ground at a speed of 11 m/s throws a baseball forward at a speed of 16 m/s


A person riding a bicycle on level ground at a speed of 11 m/s throws a baseball forward at a speed of 16 m/s relative to the bicycle at angle of 35° above the horizontal (x) direction. Ignore air drag. 


(a) If the ball is released from a height of 2.2 m, how far does the ball travel horizontally, as measured from the spot where it is released? 


(b) How far apart are the bicycle and the ball when the ball lands?

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Answer #1

Concept: the horizontal component of ball’s velocity relative to ground will be its horizontal component relative to cycle plus the velocity of cycle. Vertical component of its velocity will be simply the vertical component relative to cycle,

a) ball) in verhical direchon, tking downoa3 ad 2 2m - t= 2.088 0T 50 33m So distanc ravelle 3 22.67 m 50.33- 22-46 27 3

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