Assume that the graphs in this problem are simple undirected graphs
A. The minimum possible vertex degree in a connected undirected graph of N vertices is:
B. The maximum possible vertex degree in a connected undirected graph of N vertices is:
C. The minimum possible vertex degree in a connected undirected graph of N vertices with all vertex degree being equal is:
D. The number of edges in a completely connected undirected graph of N vertices is:
E. Minimum possible number of vertices of maximum possible vertex degree in a connected undirected graph of N vertices is:
A -
FOR ANY CONNECTED GRAPH EVERY VERTICE MUST BE CONNECTED TO ATLEAST ONE OTHER VERTICE.
SO THE MINIMUM POSSIBLE VERTEX DEGREE CAN BE 1
THINK IT OF AS A PATH WITH THE CORNER VERTEX ARE CONNECTED TO ONLY ONE ADJACENT VERTEX, SO THEIR DEGREE IS 1
B. -
THE MAXIMUM DEGREE IS POSSIBLE IN A CONNECTED GRAPH THAT IS N-1 WHEN THE EDGE IS CONNECTED TO ALL OTHER VERTEX , MEANING THERE IS AN EDGE GOING TO ALL OTHER N-1 VERTICES .
SO MAXIMUM DEGREE IS N-1
C. -
THE MINIMUM POSSIBLE DEGREE WILL BE WHEN THE ALL VERTICES FORM A RING
JUST IMAGINE THEM AS HOLDING HANDS TO EACH OTHER AND FORMING A BIG CIRCLE JUST.
SO THE MINIMUM POSSIBLE DEGREE WILL BE 2{
HEY THIS IS NOT VALID IN A SPECIAL CASE WHEN THERE ARE ONLY 2 VERTICES THEN THERE THE ANSWER WILL BE 1 }
D. -
FOR ANY CONNECTED GRAPH THERE WILL BE ALWAYS
N COMINATION 2 WAYS
SO NUMBER OF EDGES = N(N-1)/2
E-
JUST IMAGINE A VERTEX WITH ALL THE EDGES GOING OUTWARDS , LIKE HAVE YOU JUST LIKE THE DIAGRAM AS SHOWN SO
ANSWER =
1

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Assume that the graphs in this problem are simple undirected graphs A. The minimum possible vertex...
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