The meter stick is in balance condition.
Therefore, moment due to both the force about point B shall be equal.
So -
F1 * 0.40 = F2 * 0.20
=> F1 * 0.40 = 70 * 0.20
=> F1 = (70 * 0.20) / 0.40 = 35 N.
So, magnitude of F1 = 35.0 N
Question3 1 pts For the meter stick shown in the figure shown below, the force F,...
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
A 100 g meter stick sits on a fulcrum situated at the 70 cm mark. An 80 g mass hangs at 15 cm 110 g hangs from 92 cm. Determine the following: (a) The magnitude and direction of the force required to balance the stick, if it is applied at the 30 cm mark. (b) The magnitude of the normal force of the fulcrum on the stick. Include a sketch/ free body diagram, your algebra (including original equations used), and...
Force F acts at point O. Let F1 and F2 denote the components of F such that F = F1 + Fつ. The figure shows component F 1* F 4 lb Fi = 6 lb 80° 24° 0 Determine the magnitude in pounds and direction in degrees counterclockwise from the +x-axis of component F2 magnitude direction Irg counterclockwise from the +x-axis
Place an unknown mass at the 10 cm mark of the meter stick. Suspend from the other side a counter mass m2 = 300g and adjust its position until the system is in static equilibrium. Using, Στ = 0 calculate the unknown mass m². Remove the unknown mass and determine its mass on the laboratory balance. See Figure. This is the accepted mass. Calculate % error. % Error lexperimentalacceptedy 100 accepted X axis X X2 m m, m=? X =...
Two forces, F1 and F2, act at a point, as
shown in the picture. (Figure 1) F1 has a magnitude of
8.40 N and is directed at an angle of a = 59.0 ? above the
negative xaxis in the second quadrant. F2 has a
magnitude of 6.40 N and is directed at an angle of b =
54.1 ? below the negative x axis in the third
quadrant.
a) What is the x component Fx of the resultant
force? Express...
A new meter stick has dimensions of 100 cm by 2.5 cm by 0.60 cm and has a total mass of 70.0 grams. Assume the density of the stick is uniform throughout. a.) What is the linear mass density of the meter stick? b.) If somebody drills 0.50 cm diameter holes at the 60, 70, 80 and 90 cm marks, where will the new center of mass for the meter stick be located? c.) If a 50 gram mass is...
A new meter stick has dimensions of 100 cm by 2.5 cm by 0.60 cm and has a total mass of 70.0 grams. Assume the density of the stick is uniform throughout. a.) What is the linear mass density of the meter stick? b.) If somebody drills 0.50 cm diameter holes at the 60, 70, 80 and 90 cm marks, where will the new center of mass for the meter stick be located? c.) If a 50 gram mass is...
Two forces, F? 1 and F? 2, act at a point, as
shown in the picture. (Figure 1) F? 1 has a magnitude of
9.20 N and is directed at an angle of ? = 65.0 ? above the
negative xaxis in the second quadrant. F? 2 has a
magnitudeof 5.80 N and is directed at an angle of ? = 53.9
? below the negative x axis in the third quadrant.
Part A
What is the x component Fx...
Two forces of magnitude 30 newtons (N) and 70 N act on an object at angles of 30° and - 45° with the positive x-axis as shown in the figure. Find the direction and magnitude of the resultant force; that is, find F1 +F2.
10 20 30 40 50 60 70 80 90 The meterstick shown is 100 cm long. It is free to pivot around its center of gravity (CG), which is at the 50 cm mark. There is a 25.0 N block hanging from the 80 cm mark. Decide where each of the other blocks should be placed, one at a time, to balance out the 25.0 N block. 3 2 1 At what mark on the meter stick would you place...