Suppose a 500. mL flask is filled with 1.9 mol of Cl2, 0.70 mol of HCl...
Suppose a 250. mL flask is filled with 2.0 mol of Cl, 0.20 mol of CHCl, and 1.7 mol of CCI4. The following reaction becomes possible: Cl2(g) + CHCI, (8) HCI(g) +CCI (8) The equilibrium constant K for this reaction is 0.701 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places. OM 1 x s ?
Suppose a 500. mL flask is filled with 0.70 mol of H2 and 0.60 mol of HI. The following reaction becomes possible: -2H1(g) The equilibrium constant K for this reaction is 2.38 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 1.6 mol of O, and 0.70 mol of NO. The following reaction becomes possible: N2(g)02g)2NO (g) The equilibrium constant K for this reaction is 9.43 at the temperature of the flask Calculate the equilibrium molarity of NO. Round your answer to two decimal places. Ом X
Suppose a 500. mL flask is filled with 0.70 mol of NO2, 2.0 mol of NO and 0.90 mol of CO2. The following reaction becomes possible: NO2(e)+Co(g)NO(g)+Co,(g) The equilibrium constant K for this reaction is 0.331 at the temperature of the flask. Calculate the equilibrium molarity of CO. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 0.50 mol of H2 and 1.9 mol of HI. The following reaction becomes possible: H2(g)+12g2HIg The equilibrium constant K for this reaction is 4.94 at the temperature of the flask. Calculate the equilibrium molarity of H2. Round your answer to two decimal places.
Suppose a 500. ml flask is filled with 1.7 mol of Cl, and 2.0 mol of HCl. The following reaction becomes possible: H2(g) +C12(g) + 2HCl (8) The equilibrium constant K for this reaction is 7.05 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places. x o ?
Suppose a 500. ml flask is filled with 1.2 mol of Cl, and 0.80 mol of HCl. The following reaction becomes possible: H2(g) + Cl2(g) = 2HCl (g) The equilibrium constant K for this reaction is 0.419 at the temperature of the flask. Calculate the equilibrium molarity of Cl. Round your answer to two decimal places. xs ?
Suppose a 500 ml flask is filled with 1.6 mol of H, and 1.7 mol of HCl. The following reaction becomes possible: H2(g) +C12(g) + 2HCI(g) The equilibrium constant K for this reaction is 8.78 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places. OM x 6 ?
Suppose a 500.mL flask is filled with 0.10mol of Cl2, 0.40mol of HCl and 0.80mol of CCl4. The following reaction becomes possible: +Cl2gCHCl3g +HClgCCl4g The equilibrium constant K for this reaction is 0.116 at the temperature of the flask. Calculate the equilibrium molarity of HCl. Round your answer to two decimal places.
Suppose a 500. mL flask is filled with 1.0 mol of CHCl, 1.6 mol of Hcl and 0.30 mol of CCI,. The following reaction becomes p Cl(g)+CHCI (g) HCI (s)+CC () The equilibrium constant K for this reaction is 0.671 at the temperature of the flask. Calculate the equilibrium molarity of Cl,. Round your answer to two decimal places. ?