Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ = 102.8
Alternative Hypothesis, Ha: μ < 102.8
Rejection Region
This is left tailed test, for α = 0.05 and df = 15
Critical value of t is -1.753.
Hence reject H0 if t < -1.753
Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (98.9 - 102.8)/(42.3/sqrt(16))
t = -0.369
P-value Approach
P-value = 0.3586
As P-value >= 0.05, fail to reject null hypothesis.
No sufficient evidence
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