Homework Answers
1)
optical purity = observed specific rotation / specific rotation of pure
= - 47.7 / - 53.4
= 0.893
enantiomeric excess %ee = optical purity x 100
= 0.893 x 100
enantiomeric excess %ee = 89.3 %
2)
concentration = 4 / 40 = 0.1 g/ml
length = 20 cm = 2 dm
observed rotation = 14.4°
specific rotation = observed rotation / length x concentration
= 14.4° / 2 x 0.1
= 72°
specific rotation = + 72°
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