solve csc^2(x)+cot(x) -1 =0 on the interval (0,2pi)

Question

Question

Keep all answers exact where possible, otherwise round to two decimal places.

math

Answer 1

Answer #1

We know that csc^2(x)=1+cot^2(x)

So,. csc^2(x)+cot(x) -1 =0

1+cot^2(x)+cot(x)-1=0

Or cot^2(x)+cot(x)=0

cot(x)[cot(x)+1]=0

If. cot(x)=0. X=pi/2 ,3pi/2

and if. cot(x)+1=0

Cot(x)=-1. X=3pi/4 ,7pi/4

answered by: anonymous

Answer 2

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