Question

How much aluminum oxide and how much carbon are needed to prepare 395 g of aluminum...

How much aluminum oxide and how much carbon are needed to prepare 395 g of aluminum by the balanced chemical reaction (below) if the reaction proceeds to 84.1 % yield?

2Al2​O3​(s)+3C(s) 4Al(s)+3CO2​(g)

A_ ( ) g Al2O3

B_ ( ) g C   

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Answer #1

2Al203(s) + 3C(s) Al(s) 3CO2 (g) Yield of Al-395 g for 841% Yield for 100% of A-395 / 0.841-469.68 g No. of moles of Al 469.6

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