Question

Chapter S4, Problem S4/110

Determine the reaction force at A for the loaded space frame shown. Each connection may be treated as a ball-and-socket joint.

1.5 m 1 4 .8 KN 2.1 m C 4.0 m 5.5 KN 1.9 m H.-3.0m 1.9 m. E y Answer: FA =( i + k) KN

Answer 1

Take the moment about point 'E' EME=0 FBX X3.8 - 5.5x1.9 = 0 FBX = 475 KN Take the moment moment about point 'c) in x-direction about point c' EML=0 FBX X81- FAX*6:120 FAZ = FBX X211 9.75*&.1 = 10.946 KN) 61 61 Resolve Forces in x-direction FAX - FAX + Fe = 01946-9.75 +FCx=0 Fax = 1.804 Ken Take the moment about point 'A? y-direction EMAY=0 F84x4 -4.8x76=0 by = 9.12 KN

Resolve Forces in y-direction FAG - F By + 4.850 FAH – 9.12+4.8=0 I FAY = 4:32 KN) Resolve force in z-direcion FAZ + Foz + Fez=0 (1) FBZ = Fby a 9.12 KN Feza Fcx = 1804 KN put values in lqno FAZ + 9.12 +1.804 = 0 FAZ=-10.924 KN FA +16.9467 î +14.32 + f-10.924 ) KN