Two resistors, 38.0 Ω and 40.0 Ω, are connected in parallel. The current through the second resistor is 3.00 A.
(a) Determine the current in the first resistor?
(b) What is the total power supplied to the two
resistors?
Voltage across Parallel resistance is same-
V = I2 * R2
V = 3 * 40
V = 120v
(a)
Current in the first resistor -
V = I1 *R1
I1 = V/R1
I1 = 120/38
I1 = 3.16 A
Current in the first resistor I1 = 3.16 A
(b)
Power dissipated = V*I = 120 * (3 +3.16)
Total power supplied to the two resistors P = 739.2
Watt
Two resistors, 38.0 Ω and 40.0 Ω, are connected in parallel. The current through the second...
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The current through the 47 ohm resistor is 2.0 A. What
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Question 21 (3 points) Two resistors, 47 ohms and 35 ohms, are connected in parallel. The current through the 47 ohm resistor is 2.0 A. What is the total power supplied to the two resistors? 440 W 20 W 4.7 w 80 W 188 W 94 W
Two resistors, 47 ohms and 35 ohms, are connected in parallel.
The current through the 47 ohm resistor is 2.0 A. What
is the total power supplied to the two resistors?
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Two identical resistors, R1 and R2, are
connected in parallel, and this parallel combination is then
connected in series with a 100 Ω resistor, R3 as shown
below
If the total resistance of the circuit is 300 Ω what must be the
resistance of R1 and R2? If the circuit is
connected to a 30V battery, what would the current through
R1? What voltage is a dropped across R3?
100 S