Question

Its Home Courses Groups Calendar BAU BUZE BAU Library PHY1002(1-22,901-923) P... Overview Plans Resources Status and follow-up Question 21 Ww 5.000 3.00 8.00 V 4.00 2.00 5.00 8.00 V 3.00 4.00 V + 4.00 F 5.00 2.00 5.00 5000 The circuit in Figure has been connected for a long time. Find the charge on the capacitor. Your answer: Α) 20.8 μς B) 30.8 C OC) 40.8 PC 0) 50.8 uc

Answer 1

at steady state capaciter will act as open circuit. se a 5R VI е. 2e Se 8V 402 332 apply nodal analysis al node blorc', both same) 4ut AV 4v 52 st sor Vord 5.2 h 01 V-V₂ 3 + V₂ Vitu- 4 2 vilt + 1 + 3) - V2 ( 3 + ) = 0 - 44 زا lodu, 0.83V2 = 0 of node Y (or 'e', both same) t. V2-V1 3 t 2 V2-4 - Vy 2 =0 av ( 2 / 3 + ) + V2 (2+ / } + 2) = 4 Vg = 2.22v -0.83V, + 1.33V2 = 2 - aus solve (1) and (1) for CV and V₂ U₂=2.89 v (0+V1) will be the voltage gerego the capacrtor, g=C1 = 4*06x/2.22+8) 9- 40.88 UC option 'C' is correct.