A student is standing on a very slippery surface that is flat and level (perfectly horizontal)....
A student is standing on a very slippery surface that is flat and level (perfectly horizontal). She has a mass of 48.0 kg and a backpack with a mass of 12.0 kg. Consider the system to be her and her backpack.
(a)If she throws the backpack horizontally and to her right with a speed of 2.05 m/s relative to her, what is the backpack's speed (in m/s) measured relative to the centre of mass of the system?
(b)What is her speed (in m/s) measured relative to the centre of mass of the system?
(c)If she throws the backpack straight up, is the total momentum of the system conserved?
Homework Answers
a) Let her speed be u and bags speed be v relative to center of mass
by momentum conservation,
48u-12v = 0
also, u+v = 2.05
u = 0.41 m/s, v = 1.64 m/s
backpacks speed relative to center of mass = 1.64 m/s
b) her speed = 0.41 m/s
c) it will not be conserved in vertical direction, but will be conserved in horizontal
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