Question

For the given circuit, Solve for VO , ID , IL , and IZ for the following cases. Take VS=1 V , VD=0.25 V , RD=15Ω , and VZ=0.7 V .a) R1=800 Ω , RL=200 Ω
b) R1=500Ω , RL=500 Ω
c) R1=200Ω , RL=800Ω
d) R1=50Ω , RL=950Ω

(1 point) Ov: 141 ŠR lo vo @ 0 For the given circuit, Solve for Vo, ID, IL, and Iz for the following cases. Take Vs = 1V, Vp = 0.25 V, Rp = 15 12, and V2 = 0.7 V. a) Ri = 800 12, R = 200 12 b) R1 = 500 12, RL = 500 12 c) R1 = 200 S2, RL = 800 32 d) R1 = 502, RL = 950 22 VOV Iz A ILA Ip A .001

Answer 1

Reş FRIRL Utha Reus Tuth < vol In fig (2) he show that the te a m 2. have to Calculate the Uth and I y tot Rth accross Point AB and Ag (3) Vs is theunin cxt accross AB. Vth= RL vs Ritha Rilir fig 02 - diode and zener diode will not work Simultaniquely, because V2=0.70 . diode will turn on and that's why. mat Voltage ac cooss zener diode is 0.250. las Ro = Bon Run 2002 Agen With = 200 x = 0.20 so diode and zener RIARLT .. will turn off Io zo & FL= pus are too = IMA , Izso, Vo=0:21 fig(8) (b) Ri= soon Re=500 Zener diode Utha Sob x1 .560 V = D.SV V th will not work. th> up so diode turn on. | Vo =0.250 Ag (4) Iso 1-0.25, Isma Iis en het or Ilz 0.5mA Io = Is I Io = 1.5 -0.5 = IMA (c) Ri= 200 Ria 800 fig is) Vth = 0.8v : [Uth> Uz a Nth sup (But diade turn off zener diode) VaR Vp= 0.250 I Vo=0.250 So Isa Imones 3.75MA IL 20 - 0.3125MA SED

Iz = oma 1 :. In - Is - Il = 3.75 MA - 0.3125= 3.43 75 mA (as Riasor Reagoon VHF og B x1 = 0.950 so [ Uth> vol diode will on. UAB = No = 0.250 Isa 50025 ISMA IL = ora za 025 0.26315 mm Ezco] IsIs Iza (4.7368 mg] Vos 0.25 v]