Question

ENGR 103 Hw 117 (Prelab for Lab #4)-due Monday, March 18th HW #7 MUST be turned in at the beginning of class or it will not be accepted. Take a picture make a copy so that you can reference it during the lab. Do all work on this handout. CIRCUIT #1 DRAW EQUIVALENT CIRCUIT 1 kQ 11.5 V Power Supply 1.5 k02 V2 Show all work including KVL check:

Answer 1

Here, I have used mesh analysis to find the mesh current I in the given circuit. After obtaining the value for mesh current, I have obtained the values of V₁ and V_2. After finding voltages across given resistors, I have checked KVL and it's been satisfied.

The solution is as follows

Given circuit is From the above circuit I_1 = I Applying mesh analysis -11.5 V + I_1 (1 K ohm + 1.5 K ohm) = 0 therefore I_1 = 11.5 V/2.5 K ohm I_1 = I = 4.6 MA therefore v_1 = I times 1 K ohm = 4.6 mA times 1 K ohm v_1 = 4.6 v therefore v_2 = I times 1.5 k ohm = 4.6 mA times 1.5 K ohm v_2 = 6.9 v Now, according to KVL, power supply = v_1 + v_2 11.5 = 4.6 v + 6.9 v 11.5 v = 11.5 v therefore KVL has been satisfied.

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