36)
Ones place : 0 in hex (0)
Tens place : 5*2 + 2*1 = 12 in hex (A)
Hundreds place : 5*2 + 5*1 = 15 in hex (F)
Thousands place : 5*1 + 4*1 = 9 in hex (9)
Ten thousand place : 5*1 + 1*0= 5 in hex (5)
Lakhs place : 3*1 + 5*0 = 3 in hex (3)
So hex value is 0x359FA0
34) a=1010 b=0011 so b3 =0
31) c0=a3 = 1
35) a3=1 b3=0
x3=a3 xor b3 = 1 xor 0 = 1
32)
x0= b0 xor a3 = 1 xor 1 = 0
a0 + x0 + c0 = 0 + 0 + 1 now s0 =1 , c1= 0
x1 = b1 xor a3 = 1 xor 1= 0
a1+c1+x1 = 1 + 0 + 1 now s1=0 , c2=1
Hence s1=0
33) a2=0 where a=1010
Assume you are performing the calculation of (123)_10 - (3)_10. Answer questions (31) - (35) based...
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work needed, please show correct and complete answers only. thank
you.
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Please help with problem 8-56 and 8-57. Thank
you!!!
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