In exercising, a weight lifter loses 0.174 kg of water through evaporation, the heat required to evaporate the water coming from the weight lifter's body. The work done in lifting weights is 1.40E+5 J. Assuming that the latent heat of vaporization of perspiration is 2.40E+6 J/kg, find the change in the internal energy of the weight lifter.
Q = m Lf
=(0.174 kg)×(2.40×106 J/kg)
= 4.18×105 J
W = 1.40 ×105 J
By first law of thermodynamics, change in internal energy is given by,
∆U = Q - W
= (4.18 - 1.40)×105 J
= 2.78 ×105 J
In exercising, a weight lifter loses 0.174 kg of water through evaporation, the heat required to...
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