Question

You skipped this question in the previous attempt Exercise 10-8 (LO10-4, L010-5) was heed as ? server at te Grurney Fanty Restautant, Deth Bri Oenvms told. you can average S83 a diy ntps.. the populetion of daily tips is normaly diestributed with a standard deviation of $407. Over the first 45 days she was employed at the restaurant the mean daly amount of her ips wes $84.86. A the 0.05 sigrificence kevel can Ms. Brigden conclude that her daily tps average more than $83? Sate the null hypothesis and the aternate hypothesis b. State the decision rule O Reject h165 e. Compute the value of the test statistic (Round your answer to 2 decimall places d. What is your decision regarding H

Answer 1

) Given that Sample size cn) 45 doys Sample mean(X): 84-86 Sinicance level (- o5 a Null and altenate hypotheses are TE》ーat o(eo.os_cntical-value--, Snce it is Haht taited test Decision Rule: Reject Ho i z-65 Test s 乙=--1 - 84-86-83 드 3: 0 Value of the tesł stalisic is 3-of a Hee test stelistic - 3-of 65 Reject-Ho ey P-value=-p(てラ3:07). = l-P(Z <3.07) ろー-value -mT o-oo11 -