Question

4. Consider a planet in orbit about a star of mass M. Let the x-y plane correspond to the plane of the orbit, with the star a

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Given perturbation in the circular orbit r(t) = rc + Sr(t), where Sr/rc << 1 Putting r(t) in equation 1 we have GM h2 (re+ Sr

Sr=- 2 (1 - 25r(t)/re)+(1 - 35r(t)/rc) a in conta com ara el curs + GM GM G ST = - +- 28r 13 3-738r(t) Now we substitute the

Finally we have here ,

Sr(t) = - 26r(t)

Now it is given that h = r, but for rc, 0=w, i.e. frequency of the orbit T = 2/w = 2772/h = 21h/G?M? Clearly, then, örſt) =-(

This equation has the solution of the form y(x)=Acos(kx)+Bsin(kx) where, k=2*pi /T Hence for some initial condition it can be easily written as ;

27 Sr(t) = e cos(** (t – to)) Hence, complete solution will be the sum of r(t) and perturbation term .., r(t) = re + e cos(2

The modified shape will still be like a circle but along with sinusoidal variations over that circle.

Add a comment
Know the answer?
Add Answer to:
4. Consider a planet in orbit about a star of mass M. Let the x-y plane...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Problem 1 Planetary Orbits Consider the two-body problem for a planet-star system. The planet, of mass...

    Problem 1 Planetary Orbits Consider the two-body problem for a planet-star system. The planet, of mass m, is initially in a circular orbit of radius r and angular speed w about the star, of mass M. (i) What is the gravitational potential energy of the system, U? What is the kinetic energy of the planet, K? What is the total energy of the system, E = K +U? (ii) The star suddenly loses half of its mass, M + M/2....

  • A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path...

    A planet of mass m = 1.55 x 1024 kg is orbiting in a circular path a star of mass M = 9.75 x 1029 kg. The radius of the orbit is R = 4.65 x 107 km. What is the orbital period (in earth days) of the planet? Where G = 6.67 � 10-11 N�m2/kg2 and 1 day = 8.54 � 104 s. I used the formula and got T = 247 s = 0.0289 days, but the online...

  • 7Okn4. Tidal Forces: A comet of mass m and radius R approaches the Sun with a...

    7Okn4. Tidal Forces: A comet of mass m and radius R approaches the Sun with a trajectory described by C ( L/Gm2 Mn)-4 x 10° km, and eccentricity e-0.967. Will the comet break apart by tidal forces, or retun another day? (m -2 x 10 kg, R 10 km, MN-2 x 10" kg) Points (20) m! eliptcal trajectory 34 Roche Limit 5). Binary Star System: Consider a planetary system as pictured (not to scale), with the stars in a circular...

  • Please use the formulate sheet and show all steps to make sure the question is worth...

    Please use the formulate sheet and show all steps to make sure the question is worth any points a) The initial ratio of deuterium (D) to hydrogen (H) in a planet's atmosphere was 175000; however, the present ratio is 1/1500 and the initial and final abundances of D are 5 x 10° atoms per m3 and 9 x 106 atoms per m2, respectively. What fraction of deuterium has been lost, and what fraction of hydrogen has been lost in this...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT