Question

An electromagnetic wave, Ē' = ĝE.e-jkz, is traveling in the positive z-direction in a material with relative dielectric constant Er = 4. It is normally incident on the back surface of the material, passing through to air. For the given incident wave, and in terms of no and k, find ni, N2,1, 1, k1, k2,Ē”, Ě , Ñ', ħ”, Ñ.

Answer 1

LO Son dielestic 270 E = to E: - fejka " Ei, Hi- Ei= to at Er=4 se ? ,ka - E2=4 to=fito → Et,Mt Applying Boundary Condition, when the incidence power normal to the Surface both the field are tangential to the surface so Et, = Etz to hit fy= Et divide by f; then it fr et de Erler = Reflection coeff for E fields Ellei = e = bausmission coeff for & field = Hitz thens Hit Hem BH u ho han er true ۲ تنال L 12+1 man fons postres le ave m Here 1, car nomi & 7-10 % na vrh and . og Fel te beste 37 – 1852 =60x al Er= -7/t = 7 € et kiz Aus- from Its4 = 1 – 43 = 2/3 then ro of them Er . Et= %% Eu e Vkzz Ausu * TH -- = -(%)- 80 ina L- He then Hove fH; He is calculated from en we know that I am then ti= Milli ko Hi-fi - bahto ēkiz Aura 120K

Hpm to ēšky z 120K As poesírus Has tu arte har en hoe om te ho 2 Aura 1+ TH= Ep always eu - 1 + 1 - Ata Hai H4= Q H - hor ekzeuge Zuke? Aws the frequency is light of speed w= 3x108 m/s then in ais up-W + 3x10® Bxlo® – 3X10B + 13k, ß in dielectie ope_3KVP - 3:08 Bkvoll -> =2 z ka=2 clubing Auswer- M = 1206 = 120K 12 bon 1 ,60 K; - Bi= 1 kg = P2 = 2 (Assume w=3&id=cmy) Ei= to e ikz His to aj Kiz Er= %to eik, z Eq= 2 to 3 kzz Hea to zjikizo gok Hva foculki z 360K