Question

Given the data 3B 4D A 5F AH 576 klinnoie AH 34 kl


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Answer #1

consider this like algebraic equations

3B + 4D -----> A + 5F ------ (1) 576 kJ/mol

B ------> E + 1/2 F ------- (2) 84 kJ/mol

(1) - 3 (2) ==>

3B +4D - 3B ----> A + 5F -3E -3/2 F 576-3*84

4D + 3 E ------> A + 7/2 F 324 kJ/mol

Reversing the equation will make heat negative

A + 7/2 F ------> 3E + 4D - 324 kJ/mol

Answer is -324 kJ mol

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