A force of 4.29N is applied to the end of a wrench of length 0.29m at...
A force of 4.29N is applied to the end of a wrench of length 0.29m at an angle of 65 degrees as shown in the figure below. What is the magnitude (so it will be positive!) of the torque in N·m?
Homework Answers
the magnitude of the torque is,
torque = r*F*sin theta = 0.29*4.29*sin65o = 1.127 N.m
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A force of 4.29N is applied to the end of a wrench of length
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