Question

Write a program to find the element of an array, which occurs maximum number of times and its count. The program should accept the array elements as input from the user and print out the most occurring element along with its count. Hint: array size is 5. For example: Enter array elements (array size 5): 22321 Output: Max occurring element: 2. count: 3

in C language

Answer 1

#include <stdio.h>
int main(void){
  
int max=-1,ele=0,array[5];
printf("Enter array elements (array size:5):");

for(int i=0;i<5;i++){
scanf("%d",&array[i]);
}
for (int i = 0; i < 5; i++) {
int count = 0;
for (int j = 0; j < 5; j++) {
if (array[i]==array[j])
count++;
}
if (count >= max){
max = count;
ele=array[i];
}
}
if(max>-1){
printf("Max occuring elements: %d, count: %d",ele,max);
}
else
{
printf("Not exist");
}
}

Answer 2

#include <stdio.h>
void main()
{
int maxm=-1,element=0,array[5];
printf("Enter array elements (array size:5):");
for(int i=0;i<5;i++){
scanf("%d",&array[i]);
}
for (int i = 0; i < 5; i++) {
int cnt = 0;
for (int j = 0; j < 5; j++) {
if (array[i]==array[j])
cnt++;
}
if (cnt >= maxm){
maxm = cnt;
element=array[i];
}
}
if(maxm>-1){
printf("Max occuring elements: %d, cnt: %d",element,maxm);
}
else
{
printf("No repeting element is present");
}
}