A mixture of 10.325 g of iron (III) oxide and 5.734 g of aluminum metal is...

Question

Question

science chemistry

Answer 1

Answer #1

Fe2O3 + 2Al -----------> 2Fe + Al2O3

according to balanced reaction

159.69 g Fe2O3 gives 2 x 6.023 x 10²³ atoms of Fe

10.325 g Fe2O3 gives 10.325 x 2 x 6.023 x 10²³ / 159.69 = 7.80 x 10²² Fe atoms

atoms of Fe formed = 7.80 x 10²² atoms

a) 159.69 g Fe2O3 reacts with 2 x 27 g Al

10.325 g Fe2O3 reacts with 10.325 x 2 x 27 / 159.69 = 3.491 g Al

mass of Al left unreacted = 5.734 - 3.491 = 2.243 g

mass of Al left = 2.243 g

Answer 2

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