Calculate the equilibrium for the reaction given the system CH4 + 2 H2O -----------> CO2 +...
Calculate the equilibrium for the reaction
given the system
CH4 + 2 H2O -----------> CO2 + 4H2
at equilibrium, we find that 96.8 g of co2 along with 8.0 H2 and 99.2 of CH4 and 54 g of H20 were present in a 15.0 L container
Calculate the equilibrium for the reaction
[hint: convert the given values to molarity first]
Homework Answers
molCH4= 99.2g/16g/mol= 6.2 mol------> M= 6.2mol/ 15L= 0.413M
molH2O=54g/18g/mol= 3.0 mol ------> M= 3 mol/ 15L= 0.2M
molCO2= 96.8g/ 44g/mol= 2.2 mol -----> M= 2.2 mol/15L =0.147M
molH2= 8g/2g/mol= 4 mol -----> M= 4mol/15L = 0.267 M
K= [H2]4[CO2]/[H2O]2[CH4] = (0.267)4 x 0.147 / (0.2)2 x 0.413= 0.045
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Calculate the equilibrium for the reaction
given the system
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