A solution containing 8.75 ppm KMnO4 has transmittance of 0.743 in a 1.00 cm cell at 520 nm.
concentration(C) = 8.75 ppm = 0.00875 gm /L = 5.53*10-5 mole /L = 5.53*10-5 M
[ molar mass of KMnO4 = 158.034 gm and 0.00875 gm = 5.53*10-5 mole]
transmittance = 0.743
so, absorbance (A) = - log T = - log(0.743) = 0.1290
path length (l) = 1 cm
according to Lamber Beers law
[ where
molar
absorptivity]
or,
= 2332.7
M-1 cm-1
A solution containing 8.75 ppm KMnO4 has transmittance of 0.743 in a 1.00 cm cell at...
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