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17. What is the pH of the final solution when 25 ml.of 0.016 MHCI has been added to 35 ml. of0,031 MHCI at 25 C
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Answer #1

Solution:

((25 mL x 0.016 M) + (35 mL x 0.041 M)) / (25 mL + 35 mL)

= 0.0305 M HCl

Here HCl is a strong acid, so [H+] = [HCl]:
pH = - log 0.0305

= 1.5

Option C is correct

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