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About b6 of the area under the curve of the standard normal distribution is between 0.174 and z = 0.174 (or within 0.174 stan
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Answer #1

P(-0.174 0.174 < Z <0.174) INN(0,1) so, P(240-1944) - P(Z <-01 0.5691 -0.4309 = 0.1382 = [13-82]%

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