Please show steps and thought process.
weak acid pH = 1/2(pKa -logC)
pH = 1/2(-log(1.4*10^-3)-log(0.01*50))
pH = 1.577
At equivalence point salt is formed hence
pH = 7 + 1/2(pKa + logC)
C = concentration of salt
pH = 7 + 1/2(-log(1.4*10^-3)+log(0.01*50/(50+50))
pH = 7.276
Please show steps and thought process. Suppose you have a 50.00ml of 0.0100 M chloroacetic acid...
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A 10. equivalence point. L sample of vinegar, an aqueous solution of acetic acid (HC2H02),...
please solve and show work!
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