Question

In C.

// Extract the integer from the input string and convert to int int convert(char *input){ // Declare int for result extracted from input int res = 0; // Declare int for sign of result // Declare two iterators // Declare a buffer for numeric chars // Set error to zero - no error found yet // Check for space in element 1 // Check for negative integer at element 2 // Loop to copy all numeric chars to buffer // i is iterator for input string and should start at first numeric char 11 j is iterator for buffer where numeric chars are copied // This must test for chars between 0 and 9 // i gets position of last numeric char in buffer // j is now used for pow function - start at zero // Construct integer from buffer using pow j increases and i decreases // Set sign for output return res;

Answer 1

#include <stdio.h>
#include <math.h>

int convert(char *input)
{
//variable declaration and initialization
int res = 0;
int i, j=0;
char num[10];
char ch;
int error=0;
int count=0;

for (i = 0; input[i] != '\0'; i++)
{
ch = input[i];
if(isdigit(input[i]))
{
num[j] = ch;
j++;
}
else
{
error++;
}
}
i=j;
for(j=0; j<i; j++)
{
res = res + (num[j]-48) * pow(10, i-j-1);
}
  
//return statement
return res;
}

int main()
{
//character array declaration
char input[] = "1247";
int num;

//function calling
num = convert(input);
printf("%d", num);
return 0;
}

OUTPUT:

1247