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Please help explain !1. What mass of sodium sulfate is needed to prepare 150 mL of aqueous solution in which [Nal+] = 0.35 M? 0533 A 3.73 g B) 49.

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6.) moles of Nat = molarity & volume (L. = 0.35 x 0,150 = 0.025 mole M. I mole of Nasso a moles of Na are pe so, moles of Nay

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