Question

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The light beam in the figure passes through a polarizer whose transmission axis makes an angle phi with the vertical. The beam is partially polarized and partially unpolarized, and the average Intensity S bar_0 of the incident light is the sum of the average intensity S bar_0, polar of the polarized light and the average intensity S bar_0, unpolar of the polarized light: S bar_0 = S bar_0, polar + S bar_0, unpolar. The intensity S bar of the transmitted light is also the sum of two parts: S bar = S bar_0, polar + S bar_0, unpolar. As the polarizer is rotated clockwise, the intensity of the transmitted light has a minimum value of S bar = 1.4 w/m^2 when phi = 20 degree and has a maximum value of S bar = 5.6 w/m^2 when the angle is phi = phi_max. (Assume that S bar_polar is the transmitted component of S bar_0, polar and that S bar_unpolar is the transmitted component of S bar_0, unpolar.) Concepts: (i) How is S bar_unpolar related to S bar_0, unpolar ? (Do not substitute numerical values: use variables only. Use the following as necessary: phi, and S_0 unpolar to represent S bar_0, unpolar.) S bar_unpolar = (ii) How is S bar_polar related to S bar_0, polar? (Do not substitute numerical values: use variables only. Use the following as necessary: phi, phi_max and S_0 unpolar to represent S bar_0, polar.) S bar_polar =

Answer 1

i) When an un polarized light is transmitted through a polarizer, the intensity of the transmitted light is reduced by half of the intensity of the incident light irrespective of orientation of the transmission axis of the polarizer O,upoarzer wpolarizer i) According to malus law, when a polarized light is transmitted through a polarizer, the intensity of the transmitted light is, Spolar-S0 polar cos