Intensity of sound is maximum at resonance frequency.resonance
frequency of closed organ pipe is given by. f =
Resonance frequency is odd multiple of fundamental frequency
Option b is correct
Explanation
Fundamental frequency is 100 hz
Next resonance frequency is 300hz = 3× 100hz
Next resonance frequency is 500 hz = 5 × 100hz
As we can see resonance frequency is odd multiple of fundamental frequency.so option b is correct.
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The fundamental of an organ pipe that is closed at one end and open at the other end is 265.6 Hz (middle C). The second harmonic of an organ pipe that is open at both ends has the same frequency. Part A What is the length of the pipe that is closed at one end and open at the other end? PO AJĄ O O ? Submit Request Answer Part B What is the length of the pipe that is...
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An organ pipe is 2.0-m long. Assume the pipe is cylindrical with
one closd and one open end.
1) What is the longest wavelength for a standing sound wave
possible in the pipe?
2) What is the wavelength of the first 1st overtone? What is the
wavelength of the 2nd overtone?
3) If the frequency of the 4th harmonic is 290 hz, what is the
speed of sound in the pipe?
An organ pipe is 2.0-m long. Assume the pipe...
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The third harmonic Of an organ pipe of length L open at one
end has nodes at the closed end, 2L/5 from the closed end, and 4L/5
from the closed end. The open end is an antinode. What expression
describes this wave? Take the speed of sound to be 336 m/s, the
length of the pipe to be 2.0 m, and let x be the distance from the
closed end.
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explain please
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