283.3 for the equilibrium reaction below at 131.8 °C, find Ke If Kp = 2H2(g)2g)=2H20()

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science chemistry

Answer 1

Answer #1

З НЯ? +(Я? = 2H2O(0) Kp = 253. 3 Т- 131.8°C = 4о4.8K Ер = кг (етера 2.3. 3 = K. (о. o82 Х4-04-8) - ke = 1.04x

Answer 2

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