Question

Theory Elbow, Bend and Mitre The energy loss which occurs in a pipe fitting (so-called secondary loss) is commonly expressed in terms of a head loss (h) in the form: k. v2 2g K- the loss coefficient v mean velocity of flow into the fitting. Because of the complexity of flow in many fittings, K is usually determined by experiment. For the pipe fitting experiment, the head loss is calculated from two manometer readings, taken before and after each fitting, and K is then determined as Ah Sudden Enlargement 2)

Complete these tables

Answer 1

in this question you didn't clearly mentioned that what we need to find out so I filled all the empty banlks if possible mention the required objective for the problem

Value settings Short Bend(h_7.8) Elbow(h_9 - 10) Mite r head loss n_L = h_7 - h_8 v^2/2 g K head loss h_L = h_9 - h_10 v^2 /2 g K head loss h_L = h_11 - h_12 v^2/2 g K 1 2 ft 4.74 3 4.74 13 4.74 2 2 ft 4.74 3 4.74 14 7.47 Q = 8.18 lit/min = 8.18 times 0.035/60 = 4.77 times 10^- 3 ft^3/sec = 36 times 10^- 6 m^3/sec velocity = Q/A = 4.77 times 10^-3/pi/4 (0.064)^2 = n 4.77 times 10^- 3 /3.22 times 10^-3 = 1.48 ft /sec = 0.305 m?sec Therefore v^2/2 g = (0.305)^2/ 2 times 9.81 = 4.74 mm