Question

1. A ball is thrown with initial velocity of 25 m/s, directed at an angle of 600 with the ground. It landed in a pond a distance away. a) Find the initial x and y components of the velocity b) Find its velocity 2 seconds later c) What is the maximum height achieved by the ball? d) What is the ball's range? 4 pts.

Answer 1

A ball is thrown with initial velocity of 2s^2 m/s directed at an angle of 60 degree v_x_0 = v_0 cos Theta = 25 cos 60 degree 12.5 m/s v_0y = v_0 sin Theta = 25 sin 60 degree = 21.65 m/s v_x = v_x0 = 12.5 m/s v_y = v_0 y - greaterthanorequalto = 21.64 - (9.81 times 2) = 2.03 m/s rightarrow Vertical-bar v Vertical-bar = squareroot v^2_x + v^2_y = 12.7 m/s H_max = v^2_0 sin^2 Theta/2g = 24 m Range = v^2_0 sin 2 Theta/g = 55.2m