Question

1. Calculate the t value using SPSS. Please show your SPSS output. You should have 3 tables: Paired Samples Statistics, Paired Samples Correlations, and Paired Samples Test.

Pretest	Posttest	Difference	D2
3	4	-1	1
2	7	-5	25
4	6	-2	4
2	4	-2	4
1	5	-4	16
5	8	-3	9
6	9	-3	9
3	8	-5	25
2	6	-4	16
3	7	-4	16
Sum = 31	Sum = 64	Sum = -33	Sum = 125
Mean = 3.1	Mean = 6.4	Mean = -3.3	Mean – 12.5

Answer 1

Answer:-

Given that:-

Paired Samples Statistics, Paired Samples Correlations, and Paired Samples Test..

Given Sample size n = 10\For the score difference we have

D = -3,3

Sp = 1.337

Null and Alternative Hypothesis:

Houp=0

Hipp +0

$H_{0}$ : The two means are Same

$H_{a}$ : The two means are different

Test Statistic:

$t = \frac{\overline{D}}{\frac{S_{D}}{\sqrt{n}}}$

=  $\frac{-3.3}{\frac{1.337}{\sqrt{10}}}$

= -7.802

$\alpha = 0.05, df = 9$

(using t table)

Since that $\vert t\vert = 7.802 > t_{c} = 2.262,$ we Reject $H_{0}$

$\therefore$ There is enough euiclence to claim that population mean  $\mu_{1}$ is different than  $\mu_{2}$.