Question

A barbell spins around a pivot at its center (see figure). The barbell consists of two small balls, each with mass m·410 grams, a the ends of rod whose length is L 27 cm. The barbell spins with angular speed ω-50 radians/s. very or mass し、、、 Calculate Krot

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Answer #1

Formula for rotational kinematic energy is

KE_rot = (1/2)(I)(w)^2

= (0.5)(2*m*r^2)(w)^2

= (0.5)(2*0.410*0.135^2)(50)^2

KE_rot = 0.373 J

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