Formula for rotational kinematic energy is
KE_rot = (1/2)(I)(w)^2
= (0.5)(2*m*r^2)(w)^2
= (0.5)(2*0.410*0.135^2)(50)^2
KE_rot = 0.373 J
A barbell spins around a pivot at its center (see figure). The barbell consists of two...
A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 600 grams (0.6 kg), at the ends of a very low mass rod oflength d = 20 cm (0.2 m; the radius of rotation is 0.1 m). The barbell spins clockwise with angular speed 90 radians/s.
A barbell consists of two small balls, each with mass 500 grams
(0.5 kg), at the ends of a very low mass rod of length d= 20 cm
(0.2 m). The center of the barbell is mounted on the end of a low
mass rigid rod of length b= 0.3 m (see Figure). The apparatus is
started in such a way that although the rod rotates clockwise with
angular speed 80 rad/s, the barbell maintains its vertical
orientation.
Your answer...
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