Question

Calculate the binding energy per nucleon of 11B in kJ/mol. The required masses (in g/mol) are: 11.00931 g/mol H 1.00783 g/mol in 1.00867 g/mol kJ/mol nucleons Resubmit Show Approach Show Tutor Steps

Answer 1

B has 5 protons and 6 neutrons. Combined mass = (5x m.) + (6 m.) = (5 x 1.00783) + (6 x 1.00867) = 5.03915 +6.05202 = 11.09117 u Actual mass of B = 11.00931 u Mass defect Am = 11.09117 - 11.00931 = 0.08186 u = 0.08186 x 1.66054 x 10-27 kg = 1.35932 x 10-28 Kg/nuclide Binding energy = Amc2 = 1.35932 x 10-28 Kg/nuclidex (2.9979 x 10 8 m/s)2 = 1.2217 x 10-11 J/nuclide = 1.2217 x 10-14 kJ/nuclide Binding energy per mole of nuclide = 1.2217 x 10-14 kJ/nuclide x 6.022 x 1023 nuclide/mol = 7.35692 x 109 kJ/mol of nuclide Binding energy per mole of nucleon = 7.35692 x 109 kJ/mol of nuclide/9 nucleons = 6.688 x 108 kJ/mol of nucleon