Question

A certain liquid has a vapor pressure of 92.0 Torr at 23.0°C and 334.0 Torr at 45.0°C. Calculate the value of AH ap for this liquid. AHp = kJ/mol TOOLS Calculate tl x10 s liquid. boiling point:

Answer 1

Solution P, z 92 Tour P2 z 33900 Tosor TZ 230 C 2 296 K Ty z 45°C 2 31 8k According to clauzius – clapeysucon pielation - 12 R 1 T2 T ex (1275) - ekonomien + Arvop 8.319 J.mole. 318 - 296 296X318 -1.2909 z al vap 8.314 J. moet 122 94128 z J. mole - 1.2909 48.314 X 94128 22 Aliebe- 459196 x 20" 5peole Atrapz - 45.92 kJ/mole en fiz 4-5919x10*that ti i 8.319 fmolt at P = Т - latm = 760 lorer (when boid) Tьoid

222222 en (2.2759) z 5.523X103 / KY (Tboil 1 318k ) 1.9888 103k + 1 318 k = 1 Tooil 1-9885X103 K' + 3.1446 KT 2 I Tooil 103 x 4.633 1 kt - Tboil 703 boil 3 9.6331kT - z 2.15838 X 10 x 10tk z 2.158388 10²K 2 215.89 K N z - 57-166 Hence, boiling posut - 57 16°c.