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Only answer from f to i please i have already done up until e
1. m points] Consider a random sample of Industrial Engineering students, whose height (in inches) ǐnperted in the follewing table 6104-667516441ェ6491 6477 6694165 01 6560. 6522 6529 437 6451 6147 662 6506 6728 4 65.02 620 Partial output from a statistical software is previded next. For the following questions, use the partial output provided and use a 0.05 significance level for all items Variable dr SE Mean Mean 64.903 95% CI StdDev 1 242 464304 a) The 빼 shown previously illustrates the o for ammn.mmncnaldence i trval on the memn. tem I: Orwo-ided D upper bound em 2 Obsrg-sample approximation t-besed Item 3: mean O lower bound points) bd D variance standard deviation (4 points) b List all the assumptions thut need to be satisfied in order for that type of interval shown above to he valid Use as many fields an needed. (5 points ) For now, suppose at least one of the assumptions in 10b) is not valid and, hence, none of the alternative probability distributions shows in leem 2 would be appropriate for the confidence interval. Under this premise, which type of confidence interval would you recommend?(5 points) d) Determine the degrees of freedom for the confidence interval partially shown in the previous table. (5 points) ) Detemine the standard error of the mean for the confidence interval partially shown in the previous output. (5 points)
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f) X-tscoresNn < μ < x + tscore, .SNn where: x-sample mean, s-sample standard deviation, tscore-statistic with (n-1) Degrees of Freedom and α-1-confidence Percentage Degrees of Freedom -n-1 Degrees of Freedom 19-1 Degrees of Freedom 18 Calculate α = 1-confidence% α-1-0.95 Find Spread range: α = ½(0.05) α 0.025 Find t-score for αο.025 using 18 degrees of freedom. tscoreo.025 2.1009- Value can be found on Excel using tscore 2.1009 TINV(0.05,18)

G) The 95% confidence interval states that we are 95% confident that the population mean height of industrial engineering student lies within the interval 64.304 and 65.502

h) maximum allowable error is the margin of error which is 0.2849

i)

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