Question

Calculate the angular frequency of a mass on a spring which is oscillating back and forth with a period of 0.2 seconds per cycle.

Answer 1

The period(T) and angular frequency( $\omega$ ) of a mass on a spring which is oscillating back and forth are related by

$\omega=\frac{2\pi}{T}$   

We are given T = 0.2 secs per cycle. We can find ( $\omega$ ) using the above equation. Putting T = 0.2 secs/cycle

$\omega=\frac{2\pi}{0.2} = 31.42\frac{rad}{sec}$

Therefore the angular frequency( $\omega$ ) of the system $\approx$ 31 rad/sec