Question

For the System below answer the following: Hints: VA=1.134Vc and Va=1.491VB Pipe D(in) L(ft) f A 8 1500 0.020 B 6 2000 0.025 с 10 3000 0.030 Find the flowrate of water in each pipe and the pressure at point 3. Neglect minor losses. El. 200 A El. 140 B 3 El. 80 1) The Volumetric flowrate in Pipe A in ft3/s 2) The Volumetric flowrate in Pipe B in ft3/s 3) The Volumetric flowrate in Pipe C in ft3/s 4) Pressure at point 3 in Ibf/ft2

Answer 1

Answers

1. 2.6937

2. 1.0163

3. 3.71

4. 1101.948

200 \ A 140 co B 2 paralled, are As AAB head lox in A = head. Lose in B.

ст Apply energy equ blw equ b/w ① & 2 1° V, + 2- 2. + Z₂t the 29 7. - 2оо; Z, - Rо и v, Eva h, & hc } ter? LA Geap o2 x /vo x(1-13чve) - • Од 22°oo x va Т. 8/12 o2 х 22 - 2 [/i, X2 x 32 -2 he = 2.5756 V²

So, winou 2 200= va 80 t + 2.5756 Vc 2x322 V = 6.805 ft/sec ,, vo A 11134X6.805 = 7.77 ft/sec & VB :5-17585 t/sec

Volumetric flow Rate in A. Av Tax Cax7.747 QA- - 2.6937 ft²/sec Volumetric flow Rate in Bh X ( 1 ) ² x 5 17585 QB a 1.0163 H3 /pec وع 3 By continuity, Qe = QATQB = 3.7 H/sec

47 Pow, Prey око 29 w (3) 30 2 2. 4- 72 f 3 ал +2, + 14- 2 be V. - v, 2. 7 : 110 : 7: во Р «"/> ohl T go T o3 х 3ooox ( gox (o/1, х2х31- 2 ) P3 11 11. 6. 5) т. [ 66 х 62 Ч Ps = not. Qча 8+)#*